[Scip] why might this short 3 constraint program be infeasible?
Gerald Gamrath
gamrath at zib.de
Mon Sep 16 23:31:55 CEST 2013
Hi George,
the reason is simple: 'a' needs to take on the value of -14.666667 in
order to make the constraint "aval" feasible. However, if you do not
specify a lower bound for a variable, ZIMPL assumes the variable to be
nonnegative (which is consistent to the lp file format, by the way).
In order to get a free variable, you need to specify a lower bound of -
infinity, i.e.,
var a >= -infinity;
If you do this, everything works fine.
Best,
Gerald
Am 16.09.2013 21:58, schrieb George Nychis:
> Hi all,
>
> I'm trying to figure out why the solution to this short attached ZMPL
> example is infeasible. I believe that 'a' taking on the value
> of 14.666667 provides an answer, but I don't know hot SCIP is meant to
> handle that repeating digit.
>
> - George
>
>
> _______________________________________________
> Scip mailing list
> Scip at zib.de
> http://listserv.zib.de/mailman/listinfo/scip
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://listserv.zib.de/pipermail/scip/attachments/20130916/10aed37c/attachment.html>
More information about the Scip
mailing list