[SCIP] Interpreting output

[Marco Correia]

Hi,

I'm currently solving a problem where I get this output:

 time | node  | left  |LP iter|LP it/n|mem/heur|mdpt |vars |cons |rows
|cuts |sepa|confs|strbr|  dualbound   | primalbound  |  gap   | compl.
t 0.7s|     1 |     0 |     0 |     - | trivial|   0 |1580 |8299 |   0 |
  0 |  0 |   0 |   0 | 2.443041e+00 | 0.000000e+00 |    Inf | unknown
 0.8s|     1 |     0 |  1326 |     - |    47M |   0 |1580 |8300 |8298 |   0
|  0 |   1 |   0 | 1.708672e-02 | 0.000000e+00 |    Inf | unknown
 0.8s|     1 |     0 |  1326 |     - |    47M |   0 |1580 |8300 |8295 |   0
|  0 |   1 |   0 | 1.708672e-02 | 0.000000e+00 |    Inf | unknown
 0.8s|     1 |     0 |  1328 |     - |    49M |   0 |1580 |8300 |8287 |   0
|  1 |   1 |   0 | 1.460359e-02 | 0.000000e+00 |    Inf | unknown
 0.9s|     1 |     0 |  1328 |     - |    50M |   0 |1580 |8297 |8287 |   0
|  2 |   1 |   0 | 1.460359e-02 | 0.000000e+00 |    Inf | unknown
 0.9s|     1 |     0 |  1328 |     - |    50M |   0 |1580 |8297 |8287 |   0
|  2 |   1 |   0 | 1.460359e-02 | 0.000000e+00 |    Inf | unknown
 0.9s|     1 |     0 |  1328 |     - |    50M |   0 |1580 |8277 |8287 |   0
|  4 |   1 |   0 | 1.460359e-02 | 0.000000e+00 |    Inf | unknown
 1.0s|     1 |     0 |  1333 |     - |    50M |   0 |1580 |8277 |8289 |   2
|  5 |   1 |   0 | 1.319712e-02 | 0.000000e+00 |    Inf | unknown
 1.0s|     1 |     0 |  1368 |     - |    51M |   0 |1580 |8277 |8293 |   6
|  6 |   1 |   0 | 1.158039e-02 | 0.000000e+00 |    Inf | unknown
 1.5s|     1 |     0 |  1864 |     - |    52M |   0 |1580 |8278 |8293 |   6
etc...

Since the column node shows 0 and 1, does this mean SCIP spent 1.5 seconds
on solving 2 LPs ?

Is there any detailed docs about what each column mean, in particular the
"sepa", "confs"  and "strbr" (the other ones I have no doubts).

Thanks!
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